Solve for x
x=\frac{2-z-y}{3}
Solve for y
y=2-z-3x
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3x+z=2-y
Subtract y from both sides.
3x=2-y-z
Subtract z from both sides.
3x=2-z-y
The equation is in standard form.
\frac{3x}{3}=\frac{2-z-y}{3}
Divide both sides by 3.
x=\frac{2-z-y}{3}
Dividing by 3 undoes the multiplication by 3.
y+z=2-3x
Subtract 3x from both sides.
y=2-3x-z
Subtract z from both sides.
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