Solve for x
x=\frac{-7y-8}{3}
Solve for y
y=\frac{-3x-8}{7}
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3x=-8-7y
Subtract 7y from both sides.
3x=-7y-8
The equation is in standard form.
\frac{3x}{3}=\frac{-7y-8}{3}
Divide both sides by 3.
x=\frac{-7y-8}{3}
Dividing by 3 undoes the multiplication by 3.
7y=-8-3x
Subtract 3x from both sides.
7y=-3x-8
The equation is in standard form.
\frac{7y}{7}=\frac{-3x-8}{7}
Divide both sides by 7.
y=\frac{-3x-8}{7}
Dividing by 7 undoes the multiplication by 7.
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