Solve for x
x=\frac{y-7}{3}
Solve for y
y=3x+7
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3x-y=-7
Subtract 7 from both sides. Anything subtracted from zero gives its negation.
3x=-7+y
Add y to both sides.
3x=y-7
The equation is in standard form.
\frac{3x}{3}=\frac{y-7}{3}
Divide both sides by 3.
x=\frac{y-7}{3}
Dividing by 3 undoes the multiplication by 3.
7-y=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-y=-3x-7
Subtract 7 from both sides.
\frac{-y}{-1}=\frac{-3x-7}{-1}
Divide both sides by -1.
y=\frac{-3x-7}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+7
Divide -3x-7 by -1.
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Limits
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