Solve for x
x=-\frac{5y}{3}+20
Solve for y
y=-\frac{3x}{5}+12
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3x=60-5y
Subtract 5y from both sides.
\frac{3x}{3}=\frac{60-5y}{3}
Divide both sides by 3.
x=\frac{60-5y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{5y}{3}+20
Divide 60-5y by 3.
5y=60-3x
Subtract 3x from both sides.
\frac{5y}{5}=\frac{60-3x}{5}
Divide both sides by 5.
y=\frac{60-3x}{5}
Dividing by 5 undoes the multiplication by 5.
y=-\frac{3x}{5}+12
Divide 60-3x by 5.
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