Solve for x
x=\frac{7-4y}{3}
Solve for y
y=\frac{7-3x}{4}
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3x-7=-4y
Subtract 4y from both sides. Anything subtracted from zero gives its negation.
3x=-4y+7
Add 7 to both sides.
3x=7-4y
The equation is in standard form.
\frac{3x}{3}=\frac{7-4y}{3}
Divide both sides by 3.
x=\frac{7-4y}{3}
Dividing by 3 undoes the multiplication by 3.
4y-7=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
4y=-3x+7
Add 7 to both sides.
4y=7-3x
The equation is in standard form.
\frac{4y}{4}=\frac{7-3x}{4}
Divide both sides by 4.
y=\frac{7-3x}{4}
Dividing by 4 undoes the multiplication by 4.
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Limits
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