Solve for x
x=\frac{4+z-3y}{3}
Solve for y
y=\frac{4+z-3x}{3}
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3x-z=4-3y
Subtract 3y from both sides.
3x=4-3y+z
Add z to both sides.
3x=4+z-3y
The equation is in standard form.
\frac{3x}{3}=\frac{4+z-3y}{3}
Divide both sides by 3.
x=\frac{4+z-3y}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{z}{3}-y+\frac{4}{3}
Divide 4-3y+z by 3.
3y-z=4-3x
Subtract 3x from both sides.
3y=4-3x+z
Add z to both sides.
3y=4+z-3x
The equation is in standard form.
\frac{3y}{3}=\frac{4+z-3x}{3}
Divide both sides by 3.
y=\frac{4+z-3x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{z}{3}-x+\frac{4}{3}
Divide 4-3x+z by 3.
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