Solve for x
x=-\frac{2y}{3}-2
Solve for y
y=-\frac{3x}{2}-3
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3x+6=-2y
Subtract 2y from both sides. Anything subtracted from zero gives its negation.
3x=-2y-6
Subtract 6 from both sides.
\frac{3x}{3}=\frac{-2y-6}{3}
Divide both sides by 3.
x=\frac{-2y-6}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}-2
Divide -2y-6 by 3.
2y+6=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
2y=-3x-6
Subtract 6 from both sides.
\frac{2y}{2}=\frac{-3x-6}{2}
Divide both sides by 2.
y=\frac{-3x-6}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}-3
Divide -3x-6 by 2.
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