Solve for x
x=\frac{4-2y}{3}
Solve for y
y=-\frac{3x}{2}+2
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3x+3=7-2y
Subtract 2y from both sides.
3x=7-2y-3
Subtract 3 from both sides.
3x=4-2y
Subtract 3 from 7 to get 4.
\frac{3x}{3}=\frac{4-2y}{3}
Divide both sides by 3.
x=\frac{4-2y}{3}
Dividing by 3 undoes the multiplication by 3.
2y+3=7-3x
Subtract 3x from both sides.
2y=7-3x-3
Subtract 3 from both sides.
2y=4-3x
Subtract 3 from 7 to get 4.
\frac{2y}{2}=\frac{4-3x}{2}
Divide both sides by 2.
y=\frac{4-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+2
Divide 4-3x by 2.
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