Solve for x
x=0
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3x+2-\frac{1}{3}x=2
Subtract \frac{1}{3}x from both sides.
\frac{8}{3}x+2=2
Combine 3x and -\frac{1}{3}x to get \frac{8}{3}x.
\frac{8}{3}x=2-2
Subtract 2 from both sides.
\frac{8}{3}x=0
Subtract 2 from 2 to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since \frac{8}{3} is not equal to 0, x must be equal to 0.
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