Solve 3x+{left(81sqrt{81+36}right)}^2θ

$$3x+ { \left(81 \sqrt{ 81+36 } \right) }^{ 2 } \theta$$

Evaluate

$$3\left(x+255879\theta \right)$$

Solution Steps

Add 81 and 36 to get 117.

$$3x+\left(81\sqrt{117}\right)^{2}\theta$$

Factor 117=3^{2}\times 13. Rewrite the square root of the product \sqrt{3^{2}\times 13} as the product of square roots \sqrt{3^{2}}\sqrt{13}. Take the square root of 3^{2}.

$$3x+\left(81\times 3\sqrt{13}\right)^{2}\theta$$

Multiply 81 and 3 to get 243.

$$3x+\left(243\sqrt{13}\right)^{2}\theta$$

Expand \left(243\sqrt{13}\right)^{2}.

$$3x+243^{2}\left(\sqrt{13}\right)^{2}\theta$$

Calculate 243 to the power of 2 and get 59049.

$$3x+59049\left(\sqrt{13}\right)^{2}\theta$$

The square of \sqrt{13} is 13.

$$3x+59049\times 13\theta$$

Multiply 59049 and 13 to get 767637.

$$3x+767637\theta$$

Expand

$$3x+767637\theta$$

Solution Steps

Add 81 and 36 to get 117.

$$3x+\left(81\sqrt{117}\right)^{2}\theta$$

Factor 117=3^{2}\times 13. Rewrite the square root of the product \sqrt{3^{2}\times 13} as the product of square roots \sqrt{3^{2}}\sqrt{13}. Take the square root of 3^{2}.

$$3x+\left(81\times 3\sqrt{13}\right)^{2}\theta$$

Multiply 81 and 3 to get 243.

$$3x+\left(243\sqrt{13}\right)^{2}\theta$$

Expand \left(243\sqrt{13}\right)^{2}.

$$3x+243^{2}\left(\sqrt{13}\right)^{2}\theta$$

Calculate 243 to the power of 2 and get 59049.

$$3x+59049\left(\sqrt{13}\right)^{2}\theta$$

The square of \sqrt{13} is 13.

$$3x+59049\times 13\theta$$

Multiply 59049 and 13 to get 767637.

$$3x+767637\theta$$