Solve 3x*x=342

$$3x \times x=342$$

Solve for x

$$x=\sqrt{114}\approx 10.677078252$$

$$x=-\sqrt{114}\approx -10.677078252$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}=342$$

Divide both sides by 3.

$$x^{2}=\frac{342}{3}$$

Divide 342 by 3 to get 114.

$$x^{2}=114$$

Take the square root of both sides of the equation.

$$x=\sqrt{114} x=-\sqrt{114}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}=342$$

Subtract 342 from both sides.

$$3x^{2}-342=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -342 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-342\right)}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-342\right)}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\left(-342\right)}}{2\times 3}$$

Multiply -12 times -342.

$$x=\frac{0±\sqrt{4104}}{2\times 3}$$

Take the square root of 4104.

$$x=\frac{0±6\sqrt{114}}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±6\sqrt{114}}{6}$$

Now solve the equation x=\frac{0±6\sqrt{114}}{6} when ± is plus.

$$x=\sqrt{114}$$

Now solve the equation x=\frac{0±6\sqrt{114}}{6} when ± is minus.

$$x=-\sqrt{114}$$

The equation is now solved.

$$x=\sqrt{114} x=-\sqrt{114}$$