Solve 3x*x=180

$$3x \times x=180$$

Solve for x

$$x=2\sqrt{15}\approx 7.745966692$$

$$x=-2\sqrt{15}\approx -7.745966692$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}=180$$

Divide both sides by 3.

$$x^{2}=\frac{180}{3}$$

Divide 180 by 3 to get 60.

$$x^{2}=60$$

Take the square root of both sides of the equation.

$$x=2\sqrt{15} x=-2\sqrt{15}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}=180$$

Subtract 180 from both sides.

$$3x^{2}-180=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -180 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-180\right)}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-180\right)}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\left(-180\right)}}{2\times 3}$$

Multiply -12 times -180.

$$x=\frac{0±\sqrt{2160}}{2\times 3}$$

Take the square root of 2160.

$$x=\frac{0±12\sqrt{15}}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±12\sqrt{15}}{6}$$

Now solve the equation x=\frac{0±12\sqrt{15}}{6} when ± is plus.

$$x=2\sqrt{15}$$

Now solve the equation x=\frac{0±12\sqrt{15}}{6} when ± is minus.

$$x=-2\sqrt{15}$$

The equation is now solved.

$$x=2\sqrt{15} x=-2\sqrt{15}$$