Solve 3x*8x=25

$$3x \times 8x=25$$

Solve for x

$$x = \frac{5 \sqrt{6}}{12} \approx 1.020620726$$

$$x = -\frac{5 \sqrt{6}}{12} \approx -1.020620726$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}\times 8=25$$

Multiply 3 and 8 to get 24.

$$24x^{2}=25$$

Divide both sides by 24.

$$x^{2}=\frac{25}{24}$$

Take the square root of both sides of the equation.

$$x=\frac{5\sqrt{6}}{12} x=-\frac{5\sqrt{6}}{12}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}\times 8=25$$

Multiply 3 and 8 to get 24.

$$24x^{2}=25$$

Subtract 25 from both sides.

$$24x^{2}-25=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 24 for a, 0 for b, and -25 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 24\left(-25\right)}}{2\times 24}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 24\left(-25\right)}}{2\times 24}$$

Multiply -4 times 24.

$$x=\frac{0±\sqrt{-96\left(-25\right)}}{2\times 24}$$

Multiply -96 times -25.

$$x=\frac{0±\sqrt{2400}}{2\times 24}$$

Take the square root of 2400.

$$x=\frac{0±20\sqrt{6}}{2\times 24}$$

Multiply 2 times 24.

$$x=\frac{0±20\sqrt{6}}{48}$$

Now solve the equation x=\frac{0±20\sqrt{6}}{48} when ± is plus.

$$x=\frac{5\sqrt{6}}{12}$$

Now solve the equation x=\frac{0±20\sqrt{6}}{48} when ± is minus.

$$x=-\frac{5\sqrt{6}}{12}$$

The equation is now solved.

$$x=\frac{5\sqrt{6}}{12} x=-\frac{5\sqrt{6}}{12}$$