Solve 3x*4x=10

$$3x \times 4x=10$$

Solve for x

$$x=\frac{\sqrt{30}}{6}\approx 0.912870929$$

$$x=-\frac{\sqrt{30}}{6}\approx -0.912870929$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}\times 4=10$$

Multiply 3 and 4 to get 12.

$$12x^{2}=10$$

Divide both sides by 12.

$$x^{2}=\frac{10}{12}$$

Reduce the fraction \frac{10}{12} to lowest terms by extracting and canceling out 2.

$$x^{2}=\frac{5}{6}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{30}}{6} x=-\frac{\sqrt{30}}{6}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}\times 4=10$$

Multiply 3 and 4 to get 12.

$$12x^{2}=10$$

Subtract 10 from both sides.

$$12x^{2}-10=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 12 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 12\left(-10\right)}}{2\times 12}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 12\left(-10\right)}}{2\times 12}$$

Multiply -4 times 12.

$$x=\frac{0±\sqrt{-48\left(-10\right)}}{2\times 12}$$

Multiply -48 times -10.

$$x=\frac{0±\sqrt{480}}{2\times 12}$$

Take the square root of 480.

$$x=\frac{0±4\sqrt{30}}{2\times 12}$$

Multiply 2 times 12.

$$x=\frac{0±4\sqrt{30}}{24}$$

Now solve the equation x=\frac{0±4\sqrt{30}}{24} when ± is plus.

$$x=\frac{\sqrt{30}}{6}$$

Now solve the equation x=\frac{0±4\sqrt{30}}{24} when ± is minus.

$$x=-\frac{\sqrt{30}}{6}$$

The equation is now solved.

$$x=\frac{\sqrt{30}}{6} x=-\frac{\sqrt{30}}{6}$$