Solve for a
a=\frac{8}{3}-4c-2b
Solve for b
b=-\frac{a}{2}-2c+\frac{4}{3}
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3a+12c=8-6b
Subtract 6b from both sides.
3a=8-6b-12c
Subtract 12c from both sides.
3a=8-12c-6b
The equation is in standard form.
\frac{3a}{3}=\frac{8-12c-6b}{3}
Divide both sides by 3.
a=\frac{8-12c-6b}{3}
Dividing by 3 undoes the multiplication by 3.
a=\frac{8}{3}-4c-2b
Divide 8-6b-12c by 3.
6b+12c=8-3a
Subtract 3a from both sides.
6b=8-3a-12c
Subtract 12c from both sides.
6b=8-12c-3a
The equation is in standard form.
\frac{6b}{6}=\frac{8-12c-3a}{6}
Divide both sides by 6.
b=\frac{8-12c-3a}{6}
Dividing by 6 undoes the multiplication by 6.
b=-\frac{a}{2}-2c+\frac{4}{3}
Divide 8-3a-12c by 6.
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