Solve for a
a=-\left(b+2\right)
Solve for b
b=-\left(a+2\right)
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3a+7=1-3b
Subtract 3b from both sides.
3a=1-3b-7
Subtract 7 from both sides.
3a=-6-3b
Subtract 7 from 1 to get -6.
3a=-3b-6
The equation is in standard form.
\frac{3a}{3}=\frac{-3b-6}{3}
Divide both sides by 3.
a=\frac{-3b-6}{3}
Dividing by 3 undoes the multiplication by 3.
a=-b-2
Divide -6-3b by 3.
3b+7=1-3a
Subtract 3a from both sides.
3b=1-3a-7
Subtract 7 from both sides.
3b=-6-3a
Subtract 7 from 1 to get -6.
3b=-3a-6
The equation is in standard form.
\frac{3b}{3}=\frac{-3a-6}{3}
Divide both sides by 3.
b=\frac{-3a-6}{3}
Dividing by 3 undoes the multiplication by 3.
b=-a-2
Divide -6-3a by 3.
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