Solve 393^2+x*3+3*82=0

$$39 { 3 }^{ 2 } +x \cdot 3+3 \cdot 82 = 0$$

Solve for x

$$x=-199$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$39\times 9+x\times 3+3\times 82=0$$

Multiply 39 and 9 to get 351.

$$351+x\times 3+3\times 82=0$$

Multiply 3 and 82 to get 246.

$$351+x\times 3+246=0$$

Add 351 and 246 to get 597.

$$597+x\times 3=0$$

Subtract 597 from both sides. Anything subtracted from zero gives its negation.

$$x\times 3=-597$$

Divide both sides by 3.

$$x=\frac{-597}{3}$$

Divide -597 by 3 to get -199.

$$x=-199$$