Solve 391/3*402/3

$$39 \frac { 1 } { 3 } \times 40 \frac { 2 } { 3 }$$

Evaluate

$$\frac{14396}{9}\approx 1599.555555556$$

Solution Steps

Multiply 39 and 3 to get 117.

$$\frac{117+1}{3}\times \frac{40\times 3+2}{3}$$

Add 117 and 1 to get 118.

$$\frac{118}{3}\times \frac{40\times 3+2}{3}$$

Multiply 40 and 3 to get 120.

$$\frac{118}{3}\times \frac{120+2}{3}$$

Add 120 and 2 to get 122.

$$\frac{118}{3}\times \frac{122}{3}$$

Multiply \frac{118}{3} times \frac{122}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{118\times 122}{3\times 3}$$

Do the multiplications in the fraction \frac{118\times 122}{3\times 3}.

$$\frac{14396}{9}$$

Factor

$$\frac{2 ^ {2} \cdot 59 \cdot 61}{3 ^ {2}} = 1599\frac{5}{9} = 1599.5555555555557$$