Solve 39^2*(30+9)^2=30(30+9)+9(30+7)

$$39 ^ { 2 } \cdot ( 30 + 9 ) ^ { 2 } = 30 ( 30 + 9 ) + 9 ( 30 + 7 )$$

Verify

Solution Steps

Calculate 39 to the power of 2 and get 1521.

$$1521\left(30+9\right)^{2}=30\left(30+9\right)+9\left(30+7\right)$$

Add 30 and 9 to get 39.

$$1521\times 39^{2}=30\left(30+9\right)+9\left(30+7\right)$$

Calculate 39 to the power of 2 and get 1521.

$$1521\times 1521=30\left(30+9\right)+9\left(30+7\right)$$

Multiply 1521 and 1521 to get 2313441.

$$2313441=30\left(30+9\right)+9\left(30+7\right)$$

Add 30 and 9 to get 39.

$$2313441=30\times 39+9\left(30+7\right)$$

Multiply 30 and 39 to get 1170.

$$2313441=1170+9\left(30+7\right)$$

Add 30 and 7 to get 37.

$$2313441=1170+9\times 37$$

Multiply 9 and 37 to get 333.

$$2313441=1170+333$$

Add 1170 and 333 to get 1503.

$$2313441=1503$$

Compare 2313441 and 1503.

$$\text{false}$$