Solve 38x+36-10x-47

$$38 x + 36 - 10 x - 47$$

Evaluate

$$28x-11$$

Solution Steps

Combine 38x and -10x to get 28x.

$$28x+36-47$$

Subtract 47 from 36 to get -11.

$$28x-11$$

Differentiate w.r.t. x

$$28$$

Steps Using Derivative Rule for Sum

Combine 38x and -10x to get 28x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(28x+36-47)$$

Subtract 47 from 36 to get -11.

$$\frac{\mathrm{d}}{\mathrm{d}x}(28x-11)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$28x^{1-1}$$

Subtract 1 from 1.

$$28x^{0}$$

For any term t except 0, t^{0}=1.

$$28\times 1$$

For any term t, t\times 1=t and 1t=t.

$$28$$