Solve 37div(-16)+(-12)+21+(-10)-3

$$37 \div ( - 16 ) + ( - 12 ) + 21 + ( - 10 ) - 3$$

Evaluate

$$-\frac{101}{16}=-6.3125$$

Solution Steps

Fraction \frac{37}{-16} can be rewritten as -\frac{37}{16} by extracting the negative sign.

$$-\frac{37}{16}-12+21-10-3$$

Convert 12 to fraction \frac{192}{16}.

$$-\frac{37}{16}-\frac{192}{16}+21-10-3$$

Since -\frac{37}{16} and \frac{192}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-37-192}{16}+21-10-3$$

Subtract 192 from -37 to get -229.

$$-\frac{229}{16}+21-10-3$$

Convert 21 to fraction \frac{336}{16}.

$$-\frac{229}{16}+\frac{336}{16}-10-3$$

Since -\frac{229}{16} and \frac{336}{16} have the same denominator, add them by adding their numerators.

$$\frac{-229+336}{16}-10-3$$

Add -229 and 336 to get 107.

$$\frac{107}{16}-10-3$$

Convert 10 to fraction \frac{160}{16}.

$$\frac{107}{16}-\frac{160}{16}-3$$

Since \frac{107}{16} and \frac{160}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{107-160}{16}-3$$

Subtract 160 from 107 to get -53.

$$-\frac{53}{16}-3$$

Convert 3 to fraction \frac{48}{16}.

$$-\frac{53}{16}-\frac{48}{16}$$

Since -\frac{53}{16} and \frac{48}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-53-48}{16}$$

Subtract 48 from -53 to get -101.

$$-\frac{101}{16}$$

Factor

$$-\frac{101}{16} = -6\frac{5}{16} = -6.3125$$