Solve 37:(1/3)^-1+(1/2)^2*(-2)^3-(pi-3)^0

$$37 : ( \frac { 1 } { 3 } ) ^ { - 1 } + ( \frac { 1 } { 2 } ) ^ { 2 } \times ( - 2 ) ^ { 3 } - ( \pi - 3 ) ^ { 0 }$$

Evaluate

$$\frac{28}{3}\approx 9.333333333$$

Solution Steps

Calculate \frac{1}{3} to the power of -1 and get 3.

$$\frac{37}{3}+\left(\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\left(\pi -3\right)^{0}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{37}{3}+\frac{1}{4}\left(-2\right)^{3}-\left(\pi -3\right)^{0}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{37}{3}+\frac{1}{4}\left(-8\right)-\left(\pi -3\right)^{0}$$

Multiply \frac{1}{4} and -8 to get -2.

$$\frac{37}{3}-2-\left(\pi -3\right)^{0}$$

Subtract 2 from \frac{37}{3} to get \frac{31}{3}.

$$\frac{31}{3}-\left(\pi -3\right)^{0}$$

Calculate \pi -3 to the power of 0 and get 1.

$$\frac{31}{3}-1$$

Subtract 1 from \frac{31}{3} to get \frac{28}{3}.

$$\frac{28}{3}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{3} = 9\frac{1}{3} = 9.333333333333334$$