Solve 364+12h+1

$$364 + 12 h + 1$$

Differentiate w.r.t. h

$$12$$

Steps Using Derivative Rule for Sum

Add 364 and 1 to get 365.

$$\frac{\mathrm{d}}{\mathrm{d}h}(365+12h)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$12h^{1-1}$$

Subtract 1 from 1.

$$12h^{0}$$

For any term t except 0, t^{0}=1.

$$12\times 1$$

For any term t, t\times 1=t and 1t=t.

$$12$$

Evaluate

$$12h+365$$

Solution Steps

Add 364 and 1 to get 365.

$$365+12h$$