Solve 36x-x^2=62Rightarrow

$$36 x - x ^ { 2 } = 62 \Rightarrow$$

Solve for x

$$x=\sqrt{262}+18\approx 34.186414056$$

$$x=18-\sqrt{262}\approx 1.813585944$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-x^{2}+36x=62$$

Subtract 62 from both sides of the equation.

$$-x^{2}+36x-62=62-62$$

Subtracting 62 from itself leaves 0.

$$-x^{2}+36x-62=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 36 for b, and -62 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-36±\sqrt{36^{2}-4\left(-1\right)\left(-62\right)}}{2\left(-1\right)}$$

Square 36.

$$x=\frac{-36±\sqrt{1296-4\left(-1\right)\left(-62\right)}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$x=\frac{-36±\sqrt{1296+4\left(-62\right)}}{2\left(-1\right)}$$

Multiply 4 times -62.

$$x=\frac{-36±\sqrt{1296-248}}{2\left(-1\right)}$$

Add 1296 to -248.

$$x=\frac{-36±\sqrt{1048}}{2\left(-1\right)}$$

Take the square root of 1048.

$$x=\frac{-36±2\sqrt{262}}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{-36±2\sqrt{262}}{-2}$$

Now solve the equation x=\frac{-36±2\sqrt{262}}{-2} when ± is plus. Add -36 to 2\sqrt{262}.

$$x=\frac{2\sqrt{262}-36}{-2}$$

Divide -36+2\sqrt{262} by -2.

$$x=18-\sqrt{262}$$

Now solve the equation x=\frac{-36±2\sqrt{262}}{-2} when ± is minus. Subtract 2\sqrt{262} from -36.

$$x=\frac{-2\sqrt{262}-36}{-2}$$

Divide -36-2\sqrt{262} by -2.

$$x=\sqrt{262}+18$$

The equation is now solved.

$$x=18-\sqrt{262} x=\sqrt{262}+18$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-x^{2}+36x=62$$

Divide both sides by -1.

$$\frac{-x^{2}+36x}{-1}=\frac{62}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x^{2}+\frac{36}{-1}x=\frac{62}{-1}$$

Divide 36 by -1.

$$x^{2}-36x=\frac{62}{-1}$$

Divide 62 by -1.

$$x^{2}-36x=-62$$

Divide -36, the coefficient of the x term, by 2 to get -18. Then add the square of -18 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-36x+\left(-18\right)^{2}=-62+\left(-18\right)^{2}$$

Square -18.

$$x^{2}-36x+324=-62+324$$

Add -62 to 324.

$$x^{2}-36x+324=262$$

Factor x^{2}-36x+324. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-18\right)^{2}=262$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-18\right)^{2}}=\sqrt{262}$$

Simplify.

$$x-18=\sqrt{262} x-18=-\sqrt{262}$$

Add 18 to both sides of the equation.

$$x=\sqrt{262}+18 x=18-\sqrt{262}$$