Solve 36x-24px+4p^2=2px

$$36 x - 24 p x + 4 p ^ { 2 } = 2 p x$$

Solve for x

$$x=-\frac{2p^{2}}{18-13p}$$

$$p\neq \frac{18}{13}$$

Steps for Solving Linear Equation

Subtract 2px from both sides.

$$36x-24px+4p^{2}-2px=0$$

Combine -24px and -2px to get -26px.

$$36x-26px+4p^{2}=0$$

Subtract 4p^{2} from both sides. Anything subtracted from zero gives its negation.

$$36x-26px=-4p^{2}$$

Combine all terms containing x.

$$\left(36-26p\right)x=-4p^{2}$$

Divide both sides by 36-26p.

$$\frac{\left(36-26p\right)x}{36-26p}=-\frac{4p^{2}}{36-26p}$$

Dividing by 36-26p undoes the multiplication by 36-26p.

$$x=-\frac{4p^{2}}{36-26p}$$

Divide -4p^{2} by 36-26p.

$$x=-\frac{2p^{2}}{18-13p}$$

Solve for p (complex solution)

$$p=\frac{\sqrt{x\left(169x-144\right)}+13x}{4}$$

$$p=\frac{-\sqrt{x\left(169x-144\right)}+13x}{4}$$

Solve for p

$$p=\frac{\sqrt{x\left(169x-144\right)}+13x}{4}$$

$$p=\frac{-\sqrt{x\left(169x-144\right)}+13x}{4}\text{, }x\geq \frac{144}{169}\text{ or }x\leq 0$$