Solve 36x^2j^2-144

$$36 x ^ { 2 } j ^ { 2 } - 144$$

Factor

$$36\left(jx-2\right)\left(jx+2\right)$$

Solution Steps

Factor out 36.

$$36\left(x^{2}j^{2}-4\right)$$

Consider x^{2}j^{2}-4. Rewrite x^{2}j^{2}-4 as \left(xj\right)^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(xj-2\right)\left(xj+2\right)$$

Reorder the terms.

$$\left(jx-2\right)\left(jx+2\right)$$

Rewrite the complete factored expression.

$$36\left(jx-2\right)\left(jx+2\right)$$

Evaluate

$$36\left(\left(jx\right)^{2}-4\right)$$