Solve 36x^2-a^6b^4=

$$36 x ^ { 2 } - a ^ { 6 } b ^ { 4 } =$$

Factor

$$\left(6x-b^{2}a^{3}\right)\left(6x+b^{2}a^{3}\right)$$

Solution Steps

Rewrite 36x^{2}-a^{6}b^{4} as \left(6x\right)^{2}-\left(a^{3}b^{2}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(6x-a^{3}b^{2}\right)\left(6x+a^{3}b^{2}\right)$$

Reorder the terms.

$$\left(6x-b^{2}a^{3}\right)\left(6x+b^{2}a^{3}\right)$$

Evaluate

$$36x^{2}-b^{4}a^{6}$$