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\left(6x-a^{3}b^{2}\right)\left(6x+a^{3}b^{2}\right)
Rewrite 36x^{2}-a^{6}b^{4} as \left(6x\right)^{2}-\left(a^{3}b^{2}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(6x-b^{2}a^{3}\right)\left(6x+b^{2}a^{3}\right)
Reorder the terms.