Solve for t
t=\frac{9}{4\Delta }
\Delta \neq 0
Solve for Δ
\Delta =\frac{9}{4t}
t\neq 0
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36=16\Delta t
Anything plus zero gives itself.
16\Delta t=36
Swap sides so that all variable terms are on the left hand side.
\frac{16\Delta t}{16\Delta }=\frac{36}{16\Delta }
Divide both sides by 16\Delta .
t=\frac{36}{16\Delta }
Dividing by 16\Delta undoes the multiplication by 16\Delta .
t=\frac{9}{4\Delta }
Divide 36 by 16\Delta .
36=16\Delta t
Anything plus zero gives itself.
16\Delta t=36
Swap sides so that all variable terms are on the left hand side.
16t\Delta =36
The equation is in standard form.
\frac{16t\Delta }{16t}=\frac{36}{16t}
Divide both sides by 16t.
\Delta =\frac{36}{16t}
Dividing by 16t undoes the multiplication by 16t.
\Delta =\frac{9}{4t}
Divide 36 by 16t.
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