Solve 36+x^2=(x+2,4)^2

$$36 + x ^ { 2 } = ( x + 2,4 ) ^ { 2 }$$

Solve for x

$$x=6,3$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2,4\right)^{2}.

$$36+x^{2}=x^{2}+4,8x+5,76$$

Subtract x^{2} from both sides.

$$36+x^{2}-x^{2}=4,8x+5,76$$

Combine x^{2} and -x^{2} to get 0.

$$36=4,8x+5,76$$

Swap sides so that all variable terms are on the left hand side.

$$4,8x+5,76=36$$

Subtract 5,76 from both sides.

$$4,8x=36-5,76$$

Subtract 5,76 from 36 to get 30,24.

$$4,8x=30,24$$

Divide both sides by 4,8.

$$x=\frac{30,24}{4,8}$$

Expand \frac{30,24}{4,8} by multiplying both numerator and the denominator by 100.

$$x=\frac{3024}{480}$$

Reduce the fraction \frac{3024}{480} to lowest terms by extracting and canceling out 48.

$$x=\frac{63}{10}$$