Solve 36+(18-x)^2=x^2

$$36 + ( 18 - x ) ^ { 2 } = x ^ { 2 }$$

Solve for x

$$x=10$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(18-x\right)^{2}.

$$36+324-36x+x^{2}=x^{2}$$

Add 36 and 324 to get 360.

$$360-36x+x^{2}=x^{2}$$

Subtract x^{2} from both sides.

$$360-36x+x^{2}-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$360-36x=0$$

Subtract 360 from both sides. Anything subtracted from zero gives its negation.

$$-36x=-360$$

Divide both sides by -36.

$$x=\frac{-360}{-36}$$

Divide -360 by -36 to get 10.

$$x=10$$