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5\left(7m^{4}-75m^{3}+50m^{2}\right)
Factor out 5.
m^{2}\left(7m^{2}-75m+50\right)
Consider 7m^{4}-75m^{3}+50m^{2}. Factor out m^{2}.
a+b=-75 ab=7\times 50=350
Consider 7m^{2}-75m+50. Factor the expression by grouping. First, the expression needs to be rewritten as 7m^{2}+am+bm+50. To find a and b, set up a system to be solved.
-1,-350 -2,-175 -5,-70 -7,-50 -10,-35 -14,-25
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 350.
-1-350=-351 -2-175=-177 -5-70=-75 -7-50=-57 -10-35=-45 -14-25=-39
Calculate the sum for each pair.
a=-70 b=-5
The solution is the pair that gives sum -75.
\left(7m^{2}-70m\right)+\left(-5m+50\right)
Rewrite 7m^{2}-75m+50 as \left(7m^{2}-70m\right)+\left(-5m+50\right).
7m\left(m-10\right)-5\left(m-10\right)
Factor out 7m in the first and -5 in the second group.
\left(m-10\right)\left(7m-5\right)
Factor out common term m-10 by using distributive property.
5m^{2}\left(m-10\right)\left(7m-5\right)
Rewrite the complete factored expression.