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\frac{140+1}{4}\left(1-\frac{2}{3}\right)
Multiply 35 and 4 to get 140.
\frac{141}{4}\left(1-\frac{2}{3}\right)
Add 140 and 1 to get 141.
\frac{141}{4}\left(\frac{3}{3}-\frac{2}{3}\right)
Convert 1 to fraction \frac{3}{3}.
\frac{141}{4}\times \frac{3-2}{3}
Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{141}{4}\times \frac{1}{3}
Subtract 2 from 3 to get 1.
\frac{141\times 1}{4\times 3}
Multiply \frac{141}{4} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{141}{12}
Do the multiplications in the fraction \frac{141\times 1}{4\times 3}.
\frac{47}{4}
Reduce the fraction \frac{141}{12} to lowest terms by extracting and canceling out 3.