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\left(7x+9y\right)\left(49x^{2}-63xy+81y^{2}\right)
Rewrite 343x^{3}+729y^{3} as \left(7x\right)^{3}+\left(9y\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).