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\left(7p^{2}-3q\right)\left(49p^{4}+9q^{2}+21qp^{2}\right)
Rewrite 343p^{6}-27q^{3} as \left(7p^{2}\right)^{3}-\left(3q\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).