Solve 3419.46+4298.6/252sqrt{25}

$$3419.46+ \frac{ 4298.6 }{ 252 \sqrt{ 25 } }$$

Evaluate

$$\frac{21564091}{6300}\approx 3422.871587302$$

Solution Steps

Calculate the square root of 25 and get 5.

$$3419.46+\frac{4298.6}{252\times 5}$$

Multiply 252 and 5 to get 1260.

$$3419.46+\frac{4298.6}{1260}$$

Expand \frac{4298.6}{1260} by multiplying both numerator and the denominator by 10.

$$3419.46+\frac{42986}{12600}$$

Reduce the fraction \frac{42986}{12600} to lowest terms by extracting and canceling out 2.

$$3419.46+\frac{21493}{6300}$$

Convert decimal number 3419.46 to fraction \frac{341946}{100}. Reduce the fraction \frac{341946}{100} to lowest terms by extracting and canceling out 2.

$$\frac{170973}{50}+\frac{21493}{6300}$$

Least common multiple of 50 and 6300 is 6300. Convert \frac{170973}{50} and \frac{21493}{6300} to fractions with denominator 6300.

$$\frac{21542598}{6300}+\frac{21493}{6300}$$

Since \frac{21542598}{6300} and \frac{21493}{6300} have the same denominator, add them by adding their numerators.

$$\frac{21542598+21493}{6300}$$

Add 21542598 and 21493 to get 21564091.

$$\frac{21564091}{6300}$$

Factor

$$\frac{191 \cdot 112901}{7 \cdot 2 ^ {2} \cdot 3 ^ {2} \cdot 5 ^ {2}} = 3422\frac{5491}{6300} = 3422.871587301587$$