Solve 341/2-(+211/6)

$$34 \frac { 1 } { 2 } - ( + 21 \frac { 1 } { 6 } )$$

Evaluate

$$\frac{40}{3}\approx 13.333333333$$

Solution Steps

Multiply 34 and 2 to get 68.

$$\frac{68+1}{2}-\frac{21\times 6+1}{6}$$

Add 68 and 1 to get 69.

$$\frac{69}{2}-\frac{21\times 6+1}{6}$$

Multiply 21 and 6 to get 126.

$$\frac{69}{2}-\frac{126+1}{6}$$

Add 126 and 1 to get 127.

$$\frac{69}{2}-\frac{127}{6}$$

Least common multiple of 2 and 6 is 6. Convert \frac{69}{2} and \frac{127}{6} to fractions with denominator 6.

$$\frac{207}{6}-\frac{127}{6}$$

Since \frac{207}{6} and \frac{127}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{207-127}{6}$$

Subtract 127 from 207 to get 80.

$$\frac{80}{6}$$

Reduce the fraction \frac{80}{6} to lowest terms by extracting and canceling out 2.

$$\frac{40}{3}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3} = 13\frac{1}{3} = 13.333333333333334$$