Solve for x
x=\frac{1-2z-y}{33}
Solve for y
y=1-2z-33x
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33x+2z=1-y
Subtract y from both sides.
33x=1-y-2z
Subtract 2z from both sides.
33x=1-2z-y
The equation is in standard form.
\frac{33x}{33}=\frac{1-2z-y}{33}
Divide both sides by 33.
x=\frac{1-2z-y}{33}
Dividing by 33 undoes the multiplication by 33.
y+2z=1-33x
Subtract 33x from both sides.
y=1-33x-2z
Subtract 2z from both sides.
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