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33600h^{2}-7760h-60=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
h=\frac{-\left(-7760\right)±\sqrt{\left(-7760\right)^{2}-4\times 33600\left(-60\right)}}{2\times 33600}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 33600 for a, -7760 for b, and -60 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
h=\frac{-\left(-7760\right)±\sqrt{60217600-4\times 33600\left(-60\right)}}{2\times 33600}
Square -7760.
h=\frac{-\left(-7760\right)±\sqrt{60217600-134400\left(-60\right)}}{2\times 33600}
Multiply -4 times 33600.
h=\frac{-\left(-7760\right)±\sqrt{60217600+8064000}}{2\times 33600}
Multiply -134400 times -60.
h=\frac{-\left(-7760\right)±\sqrt{68281600}}{2\times 33600}
Add 60217600 to 8064000.
h=\frac{-\left(-7760\right)±80\sqrt{10669}}{2\times 33600}
Take the square root of 68281600.
h=\frac{7760±80\sqrt{10669}}{2\times 33600}
The opposite of -7760 is 7760.
h=\frac{7760±80\sqrt{10669}}{67200}
Multiply 2 times 33600.
h=\frac{80\sqrt{10669}+7760}{67200}
Now solve the equation h=\frac{7760±80\sqrt{10669}}{67200} when ± is plus. Add 7760 to 80\sqrt{10669}.
h=\frac{\sqrt{10669}+97}{840}
Divide 7760+80\sqrt{10669} by 67200.
h=\frac{7760-80\sqrt{10669}}{67200}
Now solve the equation h=\frac{7760±80\sqrt{10669}}{67200} when ± is minus. Subtract 80\sqrt{10669} from 7760.
h=\frac{97-\sqrt{10669}}{840}
Divide 7760-80\sqrt{10669} by 67200.
h=\frac{\sqrt{10669}+97}{840} h=\frac{97-\sqrt{10669}}{840}
The equation is now solved.
33600h^{2}-7760h-60=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
33600h^{2}-7760h-60-\left(-60\right)=-\left(-60\right)
Add 60 to both sides of the equation.
33600h^{2}-7760h=-\left(-60\right)
Subtracting -60 from itself leaves 0.
33600h^{2}-7760h=60
Subtract -60 from 0.
\frac{33600h^{2}-7760h}{33600}=\frac{60}{33600}
Divide both sides by 33600.
h^{2}+\left(-\frac{7760}{33600}\right)h=\frac{60}{33600}
Dividing by 33600 undoes the multiplication by 33600.
h^{2}-\frac{97}{420}h=\frac{60}{33600}
Reduce the fraction \frac{-7760}{33600} to lowest terms by extracting and canceling out 80.
h^{2}-\frac{97}{420}h=\frac{1}{560}
Reduce the fraction \frac{60}{33600} to lowest terms by extracting and canceling out 60.
h^{2}-\frac{97}{420}h+\left(-\frac{97}{840}\right)^{2}=\frac{1}{560}+\left(-\frac{97}{840}\right)^{2}
Divide -\frac{97}{420}, the coefficient of the x term, by 2 to get -\frac{97}{840}. Then add the square of -\frac{97}{840} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
h^{2}-\frac{97}{420}h+\frac{9409}{705600}=\frac{1}{560}+\frac{9409}{705600}
Square -\frac{97}{840} by squaring both the numerator and the denominator of the fraction.
h^{2}-\frac{97}{420}h+\frac{9409}{705600}=\frac{10669}{705600}
Add \frac{1}{560} to \frac{9409}{705600} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(h-\frac{97}{840}\right)^{2}=\frac{10669}{705600}
Factor h^{2}-\frac{97}{420}h+\frac{9409}{705600}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(h-\frac{97}{840}\right)^{2}}=\sqrt{\frac{10669}{705600}}
Take the square root of both sides of the equation.
h-\frac{97}{840}=\frac{\sqrt{10669}}{840} h-\frac{97}{840}=-\frac{\sqrt{10669}}{840}
Simplify.
h=\frac{\sqrt{10669}+97}{840} h=\frac{97-\sqrt{10669}}{840}
Add \frac{97}{840} to both sides of the equation.
x ^ 2 -\frac{97}{420}x -\frac{1}{560} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 33600
r + s = \frac{97}{420} rs = -\frac{1}{560}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{97}{840} - u s = \frac{97}{840} + u
Two numbers r and s sum up to \frac{97}{420} exactly when the average of the two numbers is \frac{1}{2}*\frac{97}{420} = \frac{97}{840}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath-gzdabgg4ehffg0hf.b01.azurefd.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{97}{840} - u) (\frac{97}{840} + u) = -\frac{1}{560}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{1}{560}
\frac{235225}{862784} - u^2 = -\frac{1}{560}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{1}{560}-\frac{235225}{862784} = \frac{266725}{862784}
Simplify the expression by subtracting \frac{235225}{862784} on both sides
u^2 = -\frac{266725}{862784} u = \pm\sqrt{-\frac{266725}{862784}} = \pm \frac{\sqrt{266725}}{\sqrt{862784}}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{97}{840} - \frac{\sqrt{266725}}{\sqrt{862784}}i = -0.007 s = \frac{97}{840} + \frac{\sqrt{266725}}{\sqrt{862784}}i = 0.238
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.