Solve 33(11-3.3)*sqrt{3+3^2}

$$33(11-3.3) \times \sqrt{ 3+ { 3 }^{ 2 } }$$

Evaluate

$$\frac{2541\sqrt{3}}{5}\approx 880.228220407$$

Solution Steps

Subtract 3.3 from 11 to get 7.7.

$$33\times 7.7\sqrt{3+3^{2}}$$

Multiply 33 and 7.7 to get 254.1.

$$254.1\sqrt{3+3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$254.1\sqrt{3+9}$$

Add 3 and 9 to get 12.

$$254.1\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$254.1\times 2\sqrt{3}$$

Multiply 254.1 and 2 to get 508.2.

$$508.2\sqrt{3}$$