Solve for a
a=-\frac{3b}{16}-\frac{3c}{8}+\frac{49}{16}
Solve for b
b=-\frac{16a}{3}-2c+\frac{49}{3}
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32a+12c=98-6b
Subtract 6b from both sides.
32a=98-6b-12c
Subtract 12c from both sides.
32a=98-12c-6b
The equation is in standard form.
\frac{32a}{32}=\frac{98-12c-6b}{32}
Divide both sides by 32.
a=\frac{98-12c-6b}{32}
Dividing by 32 undoes the multiplication by 32.
a=-\frac{3b}{16}-\frac{3c}{8}+\frac{49}{16}
Divide 98-6b-12c by 32.
6b+12c=98-32a
Subtract 32a from both sides.
6b=98-32a-12c
Subtract 12c from both sides.
6b=98-12c-32a
The equation is in standard form.
\frac{6b}{6}=\frac{98-12c-32a}{6}
Divide both sides by 6.
b=\frac{98-12c-32a}{6}
Dividing by 6 undoes the multiplication by 6.
b=-\frac{16a}{3}-2c+\frac{49}{3}
Divide 98-32a-12c by 6.
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