Solve 321*28

$$321 \times 28$$

Evaluate

$$8988$$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9}321\\\underline{\times\phantom{99}28}\\\end{array}$$

Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 321 with 8. Write the result 2568 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}321\\\underline{\times\phantom{99}28}\\\phantom{\times}2568\\\end{array}$$

Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 321 with 2. Write the result 642 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}321\\\underline{\times\phantom{99}28}\\\phantom{\times}2568\\\underline{\phantom{\times}642\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times9}321\\\underline{\times\phantom{99}28}\\\phantom{\times}2568\\\underline{\phantom{\times}642\phantom{9}}\\\phantom{\times}8988\end{array}$$

Factor

$$2^{2}\times 3\times 7\times 107$$