Solve for x
x=\frac{7-3y}{32}
Solve for y
y=\frac{7-32x}{3}
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32x=7-3y
Subtract 3y from both sides.
\frac{32x}{32}=\frac{7-3y}{32}
Divide both sides by 32.
x=\frac{7-3y}{32}
Dividing by 32 undoes the multiplication by 32.
3y=7-32x
Subtract 32x from both sides.
\frac{3y}{3}=\frac{7-32x}{3}
Divide both sides by 3.
y=\frac{7-32x}{3}
Dividing by 3 undoes the multiplication by 3.
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