Solve 32*10^3(-2)+543*10^4(-3)=

$$32 \times { 10 }^{ 3(-2) } +543 \times { 10 }^{ 4(-3) } =$$

Evaluate

$$\frac{32000543}{1000000000000}\approx 0.000032001$$

Solution Steps

Multiply 3 and -2 to get -6.

$$32\times 10^{-6}+543\times 10^{4\left(-3\right)}$$

Calculate 10 to the power of -6 and get \frac{1}{1000000}.

$$32\times \frac{1}{1000000}+543\times 10^{4\left(-3\right)}$$

Multiply 32 and \frac{1}{1000000} to get \frac{1}{31250}.

$$\frac{1}{31250}+543\times 10^{4\left(-3\right)}$$

Multiply 4 and -3 to get -12.

$$\frac{1}{31250}+543\times 10^{-12}$$

Calculate 10 to the power of -12 and get \frac{1}{1000000000000}.

$$\frac{1}{31250}+543\times \frac{1}{1000000000000}$$

Multiply 543 and \frac{1}{1000000000000} to get \frac{543}{1000000000000}.

$$\frac{1}{31250}+\frac{543}{1000000000000}$$

Add \frac{1}{31250} and \frac{543}{1000000000000} to get \frac{32000543}{1000000000000}.

$$\frac{32000543}{1000000000000}$$

Factor

$$\frac{29 \cdot 1103467}{2 ^ {12} \cdot 5 ^ {12}} = 3.2000542999999992 \times 10^{-5}$$