Solve 31-lceil16-(11-3*2)rceil+8(-2)

$$31- \lceil 16-(11-3 \times 2) \rceil +8(-2)$$

Evaluate

$$4$$

Solution Steps

Multiply 3 and 2 to get 6.

$$31-\lceil 16-\left(11-6\right)\rceil +8\left(-2\right)$$

Subtract 6 from 11 to get 5.

$$31-\lceil 16-5\rceil +8\left(-2\right)$$

Subtract 5 from 16 to get 11.

$$31-\lceil 11\rceil +8\left(-2\right)$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 11 is 11.

$$31-11+8\left(-2\right)$$

Subtract 11 from 31 to get 20.

$$20+8\left(-2\right)$$

Multiply 8 and -2 to get -16.

$$20-16$$

Subtract 16 from 20 to get 4.

$$4$$

Factor

$$2^{2}$$