Solve 31(-6/5+1/3)*(3/26)

$$31 ( \frac { - 6 } { 5 } + \frac { 1 } { 3 } ) * ( \frac { 3 } { 26 } )$$

Evaluate

$$-\frac{31}{10}=-3.1$$

Solution Steps

Fraction \frac{-6}{5} can be rewritten as -\frac{6}{5} by extracting the negative sign.

$$31\left(-\frac{6}{5}+\frac{1}{3}\right)\times \frac{3}{26}$$

Least common multiple of 5 and 3 is 15. Convert -\frac{6}{5} and \frac{1}{3} to fractions with denominator 15.

$$31\left(-\frac{18}{15}+\frac{5}{15}\right)\times \frac{3}{26}$$

Since -\frac{18}{15} and \frac{5}{15} have the same denominator, add them by adding their numerators.

$$31\times \frac{-18+5}{15}\times \frac{3}{26}$$

Add -18 and 5 to get -13.

$$31\left(-\frac{13}{15}\right)\times \frac{3}{26}$$

Express 31\left(-\frac{13}{15}\right) as a single fraction.

$$\frac{31\left(-13\right)}{15}\times \frac{3}{26}$$

Multiply 31 and -13 to get -403.

$$\frac{-403}{15}\times \frac{3}{26}$$

Fraction \frac{-403}{15} can be rewritten as -\frac{403}{15} by extracting the negative sign.

$$-\frac{403}{15}\times \frac{3}{26}$$

Multiply -\frac{403}{15} times \frac{3}{26} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-403\times 3}{15\times 26}$$

Do the multiplications in the fraction \frac{-403\times 3}{15\times 26}.

$$\frac{-1209}{390}$$

Reduce the fraction \frac{-1209}{390} to lowest terms by extracting and canceling out 39.

$$-\frac{31}{10}$$

Factor

$$-\frac{31}{10} = -3\frac{1}{10} = -3.1$$