Solve 30x+53geq18x-83

$$30x+53 \geq 18x-83$$

Solve for x

$$x\geq -\frac{34}{3}$$

Solution Steps

Subtract 18x from both sides.

$$30x+53-18x\geq -83$$

Combine 30x and -18x to get 12x.

$$12x+53\geq -83$$

Subtract 53 from both sides.

$$12x\geq -83-53$$

Subtract 53 from -83 to get -136.

$$12x\geq -136$$

Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.

$$x\geq \frac{-136}{12}$$

Reduce the fraction \frac{-136}{12} to lowest terms by extracting and canceling out 4.

$$x\geq -\frac{34}{3}$$