Solve 309+40left(70-aright)leq2500

$$309+40 \left( 70-a \right) \leq 2500$$

Solve for a

$$a\geq \frac{609}{40}$$

Solution Steps

Use the distributive property to multiply 40 by 70-a.

$$309+2800-40a\leq 2500$$

Add 309 and 2800 to get 3109.

$$3109-40a\leq 2500$$

Subtract 3109 from both sides.

$$-40a\leq 2500-3109$$

Subtract 3109 from 2500 to get -609.

$$-40a\leq -609$$

Divide both sides by -40. Since -40 is negative, the inequality direction is changed.

$$a\geq \frac{-609}{-40}$$

Fraction \frac{-609}{-40} can be simplified to \frac{609}{40} by removing the negative sign from both the numerator and the denominator.

$$a\geq \frac{609}{40}$$