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6\left(512m^{3}+27n^{3}\right)
Factor out 6.
\left(8m+3n\right)\left(64m^{2}-24mn+9n^{2}\right)
Consider 512m^{3}+27n^{3}. Rewrite 512m^{3}+27n^{3} as \left(8m\right)^{3}+\left(3n\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
6\left(8m+3n\right)\left(64m^{2}-24mn+9n^{2}\right)
Rewrite the complete factored expression.