Evaluate
30+295x-40x^{2}
Factor
-40\left(x-\frac{59-\sqrt{3673}}{16}\right)\left(x-\frac{\sqrt{3673}+59}{16}\right)
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295x+20+10-40x^{2}
Combine 300x and -5x to get 295x.
295x+30-40x^{2}
Add 20 and 10 to get 30.
factor(295x+20+10-40x^{2})
Combine 300x and -5x to get 295x.
factor(295x+30-40x^{2})
Add 20 and 10 to get 30.
-40x^{2}+295x+30=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-295±\sqrt{295^{2}-4\left(-40\right)\times 30}}{2\left(-40\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-295±\sqrt{87025-4\left(-40\right)\times 30}}{2\left(-40\right)}
Square 295.
x=\frac{-295±\sqrt{87025+160\times 30}}{2\left(-40\right)}
Multiply -4 times -40.
x=\frac{-295±\sqrt{87025+4800}}{2\left(-40\right)}
Multiply 160 times 30.
x=\frac{-295±\sqrt{91825}}{2\left(-40\right)}
Add 87025 to 4800.
x=\frac{-295±5\sqrt{3673}}{2\left(-40\right)}
Take the square root of 91825.
x=\frac{-295±5\sqrt{3673}}{-80}
Multiply 2 times -40.
x=\frac{5\sqrt{3673}-295}{-80}
Now solve the equation x=\frac{-295±5\sqrt{3673}}{-80} when ± is plus. Add -295 to 5\sqrt{3673}.
x=\frac{59-\sqrt{3673}}{16}
Divide -295+5\sqrt{3673} by -80.
x=\frac{-5\sqrt{3673}-295}{-80}
Now solve the equation x=\frac{-295±5\sqrt{3673}}{-80} when ± is minus. Subtract 5\sqrt{3673} from -295.
x=\frac{\sqrt{3673}+59}{16}
Divide -295-5\sqrt{3673} by -80.
-40x^{2}+295x+30=-40\left(x-\frac{59-\sqrt{3673}}{16}\right)\left(x-\frac{\sqrt{3673}+59}{16}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{59-\sqrt{3673}}{16} for x_{1} and \frac{59+\sqrt{3673}}{16} for x_{2}.
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