Solve 300+1/2(100+40)*3+1/2*(40-120)*3+1/2(-120-150)*4

$$300 + \frac { 1 } { 2 } ( 100 + 40 ) \times 3 + \frac { 1 } { 2 } \times ( 40 - 120 ) \times 3 + \frac { 1 } { 2 } ( - 120 - 150 ) \times 4$$

Evaluate

$$-150$$

Solution Steps

Add 100 and 40 to get 140.

$$300+\frac{1}{2}\times 140\times 3+\frac{1}{2}\left(40-120\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Multiply \frac{1}{2} and 140 to get \frac{140}{2}.

$$300+\frac{140}{2}\times 3+\frac{1}{2}\left(40-120\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Divide 140 by 2 to get 70.

$$300+70\times 3+\frac{1}{2}\left(40-120\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Multiply 70 and 3 to get 210.

$$300+210+\frac{1}{2}\left(40-120\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Add 300 and 210 to get 510.

$$510+\frac{1}{2}\left(40-120\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Subtract 120 from 40 to get -80.

$$510+\frac{1}{2}\left(-80\right)\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Multiply \frac{1}{2} and -80 to get \frac{-80}{2}.

$$510+\frac{-80}{2}\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Divide -80 by 2 to get -40.

$$510-40\times 3+\frac{1}{2}\left(-120-150\right)\times 4$$

Multiply -40 and 3 to get -120.

$$510-120+\frac{1}{2}\left(-120-150\right)\times 4$$

Subtract 120 from 510 to get 390.

$$390+\frac{1}{2}\left(-120-150\right)\times 4$$

Subtract 150 from -120 to get -270.

$$390+\frac{1}{2}\left(-270\right)\times 4$$

Multiply \frac{1}{2} and -270 to get \frac{-270}{2}.

$$390+\frac{-270}{2}\times 4$$

Divide -270 by 2 to get -135.

$$390-135\times 4$$

Multiply -135 and 4 to get -540.

$$390-540$$

Subtract 540 from 390 to get -150.

$$-150$$

Factor

$$-150$$